Today we discuss how to use the chain rule formula, dy/dx = dy/du * du/dx, to differentiate equations.

In this lesson we differentiate a composite function e.g. y=(x+2)^2 using the chain rule. We talk about how to differentiate it the old way (by expanding first) and then how to differentiate it the new way (using the chain rule). It is a lot quicker to use the chain rule if you have to differentiate …

Following the previous lesson where we differentiated the displacement equation to get the velocity equation, we now differentiate the velocity equation to get the acceleration equation.

Today we apply what we have learned in differentiation to differentiate a displacement equation to give us the velocity equation.

In this lesson we talk about some of the different notations you will come across when dealing with calculus that mean the same thing (e.g. y=f(x), dy/dx=f'(x)=y’).

In this lesson you learn how to find the second derivative by differentiating a function twice.

Today we talk about how to find the gradient function without using the differentiation formula.

So now that you have learned the rule for differentiation, let’s differentiate some more equations.

In this lesson we talk about the process of differentiation – finding the “gradient function” of a function. We also do a sample problem where we find the gradient at a point on a curve without drawing the tangent line (by differentiating and then substituting in the x value of the point).

In this lesson we talk about how the gradient of the tangent line to a curve is the same as gradient of the curve at the point of contact.