In this simple Markov Chains tutorial, you learn about the transition matrix and states and how to use them to solve a simple problem.
In this tutorial we show you step by step how to tackle a difficult modelling and problem solving question involving linear transformations of curves. You will need knowledge of linear transformations of curves, as well as being familiar with quadratic equations in general (solving, finding x/y intercepts).
One of my subscribers e-mailed me this hard matrix equation to solve. I decided to make a video to help them do it. Had to rearrange the equation by using the distributive law, then a combination of multiplying by inverses at the front/back as well as matrix subtraction, then some substitution simultaneous equation solving.
In this lesson we talk about what happens when the transformation matrix is singular – no matter where your original point is on the plane, the image will form a straight line.
In this tutorial, we talk about how to go back to the original point if we are given an image and the transformation that was conducted.
In this tutorial we discuss how to construct the transformation matrix to transform a point in the line y=mx where m=tan(theta) where theta is the angle between the line and the x axis.
In this lesson we talked about how to reflect a point in the line y=x.
In part 1 we discussed reflection in the x axis. In this lesson we show you how to construct the transformation matrix for reflection in the y axis. Next lesson we will do reflection in the line y=x.
In this series we’re going to focus on constructing the transformation matrix for reflections. Start with reflecting in the x axis, which we have touched on previously. In subsequent lessons we’re going to talk about reflection in the y axis, reflection in the line y=x, and reflection in the line y=mx.
In this tutorial we rotated the line y=2x by 25 degrees about the origin and found the image of the line to be y’=37.25x’. We show you how to do it step by step.